C语言题目14
//实现输入任意两个若干位的整数,进行加法,计算并返回加和后的结果。 //(注意两个整数可以足够大,以至于double都会溢出。只要系统内存够用, //此加法都要正常运行) #include"stdio.h" #include"stdlib.h" typedef struct node{ int x; struct node *next; struct node *before; }llnode; int charToNumber(char c) { return c-48; } void getNumber(llnode* tail) { char c; llnode *p; llnode *q; q = tail; printf("请输入一个整数, 输入完成后敲击回车:"); while(1) { c = getchar(); if(c == '\n') { break; } else { p = (llnode *)malloc(sizeof(llnode)); p->x = charToNumber(c); p->before = NULL; if(tail->x == 0) { tail->before = p; p->next = tail; tail->x = tail->x+1; } else { q = tail->before; q->next = p; p->before = q; p->next = tail; tail->before = p; q = p; tail->x = tail->x+1; } } } } void addNumber(llnode* ctail, llnode* atail, llnode* btail) { int i=0; int alength = atail->x; int blength = btail->x; llnode *pshort; llnode *plong; llnode *ps; llnode *pl; llnode *p; llnode *q; int a; int b; int nextc; int thisc; int d; if(alength>blength) { pshort = btail; plong = atail; } else { pshort = atail; plong = btail; } ps = pshort->before; pl = plong->before; while(i<pshort->x) { thisc = nextc; if(ps->x + pl->x >=10) { nextc = 1; d = (ps->x + pl->x)%10; } else { nextc = 0; d = (ps->x + pl->x); } ps = ps->before; pl = pl->before; p = (llnode *)malloc(sizeof(llnode)); p->x = d+thisc; p->before = NULL; if(ctail->x == 0) { ctail->before = p; p->next = ctail; ctail->x = ctail->x+1; q = p; } else { p->next = q; q->before = p; q = p; ctail->x = ctail->x+1; } i = i+1; } while(i<plong->x) { if(i == pshort->x) { p = (llnode *)malloc(sizeof(llnode)); p->x = (pl->x)+nextc; p->before = NULL; } else { p = (llnode *)malloc(sizeof(llnode)); p->x = pl->x; p->before = NULL; } p->next = q; q->before = p; q = p; ctail->x = ctail->x+1; pl = pl->before; i = i+1; } } void showResult(llnode* ctail) { llnode *p; p = ctail; while(p->before != NULL) { p = p->before; } while(p != ctail) { printf("%d",p->x); p = p->next; } printf("\n"); } int main() { llnode *atail = (llnode *)malloc(sizeof(llnode)); llnode *btail = (llnode *)malloc(sizeof(llnode)); llnode *ctail = (llnode *)malloc(sizeof(llnode)); llnode *p=atail; atail->x = 0; btail->x = 0; ctail->x = 0; atail->next = NULL; btail->next = NULL; ctail->next = NULL; getNumber(atail); getNumber(btail); addNumber(ctail, atail, btail); showResult(ctail); return 1; }